Question

For what value of K, will K,2K-1 and 2K + 7 are the consecutive terms of an A.P.​

Answer 1

Answer:

9

Step-by-step explanation:

d=(2k-1)-k

also, d=(2k+7)-(2k-1)

so, (2k-1)-k=(2k+7)-(2k-1)

2k-1-k = 2k+7-2k+1

k-1 = 8

k=8+1

k=9

Answer 2

The value of K = 9

Given :

K , 2K - 1 and 2K + 7 are the consecutive terms of an AP

To find :

The value of K

Solution :

Step 1 of 2 :

Form the equation to find the value of K

Here it is given that K , 2K - 1 and 2K + 7 are the consecutive terms of an AP

We know that if three terms a , b , c are in Arithmetic progression then 2b = a + c

By the given condition

2(2K - 1) = K + (2K + 7)

Step 2 of 2 :

Find the value of K

2(2K - 1) = K + (2K + 7)

⇒ 4K - 2 = K + 2K + 7

⇒ 4K - 2 = 3K + 7

⇒ 4K - 3K = 7 + 2

⇒ K = 9

Hence the required value of K = 9

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