Question

For what value of k will k + 9, 2 k ‒ 1 and 2k + 7 are the consecutive terms of an A.P.?​

Answer 1

Answer:

your answer is here !

Step-by-step explanation:

If three terms x, y and z are in A.P. then, 2 y = x + z

Since k + 9, 2 k ‒ 1 and 2 k + 7 are in A.P.

∴ 2(2k − 1) = (k + 9) + (2k + 7)

⟹ 4k – 2 = 3k + 16

⟹ k = 18

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Answer 2

Answer:

k = 18

Step-by-step explanation:

We know in an A.P. , the Common Difference ,ie, "d" remains a constant .

According to the Q,

>> d = d

>> (2k - 1) - (k + 9) = (2k + 7) - (2k - 1)

On Opening the Bracket:

>> 2k - 1 - k - 9 = 2k + 7 - 2k + 1

>> 2k - k -2k + 2k = 7 + 1 + 1 + 9

>> 2k - k = 18

>> k = 18

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