for what value of k will k+9,2k-1, 2k+7 ae consecutive tetms of A.P
riyarajeendran:
do u know the correct answer
Answers
Answered by
1
.......this is the correct answer
Attachments:
Answered by
0
Answer:
Step-by-step explanation:
As k+9, 2k-1 and 2k+7 are consecutive terms of A.P
Let k+9 =a1 , 2k-1=a2 and 2k+7=a3
Therefore. d= a2-a1 =a3-a2
d= 2k-1-k-9=2k+7-2k+1
= k-10=8
= k= 8+10
= k= 18
Similar questions