for what value of k will k+9,2k-1 , 2k+7 be the consecutive term of an AP
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(2k-1) - (k+9) = (2k+7) - (2k-1)
2k - 1 - k - 9 = 2k + 7 - 2k + 1
k - 10 = 8
k = 18.
2k - 1 - k - 9 = 2k + 7 - 2k + 1
k - 10 = 8
k = 18.
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