Question

for what value of k will k+9,2k-1,2k+7are the consecutive term of the AP

Answer 1

for terms to be in ap.... common diff should be same
(2k-1)-(k+9)=(2k+7)-(2k-1)
k-10=8
k=18
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Answer 2

common difference should be same.
so
(2k-1)-(k+9)=(2k+7)-(2k-1)
2k-1-k-9=2k+7-2k+1
k-10=8
k=8+10
k=18 ans

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