For what value of k will k+9,2k-1&2k+7 are the consecutive term of an ap
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d1=a2-a1
=2k-1-k-9
d2=2k+7-(2k-1)
d1=d2(consecutive terms of An ap has equal common difference)
2k-1-k-9=2k+7-2k+1
Hence value of k=18.answer
=2k-1-k-9
d2=2k+7-(2k-1)
d1=d2(consecutive terms of An ap has equal common difference)
2k-1-k-9=2k+7-2k+1
Hence value of k=18.answer
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