Question

for what value of k will k+9,2k-1 and 2k+7 are consecutive terms of A.P

Answer 1

so ur answer is 18 i hope it help

Answer 2

a1 = k+9

a2 = 2k-1

a3 = 2k+7

a2-a1 = a3-a2  

2k-1 -k-9 = 2k+7-2k+1

3k-10 = 8

3k = 18

k = 18/3 = 6