for what value of k will k+9 ,2k-1 and 2k+7 are consecutive term of an ap
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Answered by
6
may be...my ans is ryt.
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Answered by
2
Answer:
k=18
Step-by-step explanation: let k+9=a
2k-1=b
2k+7=c
b-a=c-b
2k-1-(k+9)=2k+7-(2k-1)
2k-1-k-9=2k+7-2k+1
k-10=8
k=8+10
k=18
⊕⊕ hope it helps ⊕⊕
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