For what value of k will k + 9, 2k - 1 and
2k + 7 are the consecutive terms of an A.P.?
Answers
Answered by
24
Answer:
hey there
common difference = d
d = 2k - 1 - (k + 9) = 2k + 7 - ( 2k - 1)
2k - 1 - k - 9 = 2k + 7 - 2k + 1
k - 10 = 8
k = 18
Hope it helps you
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Answered by
10
Answer:
18
Step-by-step explanation:
For an A.P. ,
t2 - t1 = t3 -t2
2k-1 - k - 9 = 2k+7 - 2k +1
k = 8+10
k = 18
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