Math, asked by kiranpreetkaur38004, 11 months ago

For what value of k will k + 9, 2k - 1 and
2k + 7 are the consecutive terms of an A.P.?​

Answers

Answered by kabirsingh18
24

Answer:

hey there

common difference = d

d = 2k - 1 - (k + 9) = 2k + 7 - ( 2k - 1)

2k - 1 - k - 9 = 2k + 7 - 2k + 1

k - 10 = 8

k = 18

Hope it helps you

Mark it as branliest please

Answered by padmavilluri789
10

Answer:

18

Step-by-step explanation:

For an A.P. ,

t2 - t1 = t3 -t2

2k-1 - k - 9 = 2k+7 - 2k +1

k = 8+10

k = 18

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