Question

for what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P. ?​

Answer 1

Answer:

Below see. Pls mark as brainliest.

Step-by-step explanation:

We know that in any AP, a2-a1=a3-a2

Let k+9 be a1,

2k-1 be a2,

2k+7 be a3,

So 2k-1-(k+9)=2k+7-(2k-1)

→2k-1-k-9=2k+7-2k+1

→k-10=8

→k=18

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