Question

for what value of k will k+9, 2k-1, and 2k+7 are the consecutive terms of an A.P?

Answer 1

I hope its help u....

Answer 2

Answer:

• 18.

Step-by-step explanation:

We have,

=> a = k + 9

=> b = 2k - 1

=> c = 2k + 7

We know,

For a progression to be in A.P, we have 2b = a + c

Hence,

⇒ 2(2k - 1) = (k + 9) + (2k + 7)

⇒ 4k - 2 = k + 9 + 2k + 7

⇒ 4k - k - 2k = 7 + 9 + 2

⇒ k = 18

∴ The value of k is 18.