Question

For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P.?


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Answer 1

Answer:

Explanation:

Let  

k+9=a

2k−1=b

2k+7=c

To be in AP,

a+c=2b

k+9+2k+7=2(2k−1)

⇒ 3k+16=4k−2

⇒ 3k−4k=−2−16

⇒ −k=−18

∴k=18

For k=18, the terms k+9,2k−1,2k+7 are in A.P