Question

For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an A.P.?

Please anyone solve this question please

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Class 10th
Chapter- Coordinate Geometry ​

Answer 1

let ":"

k+9=a

2k-1=b

2k+7=c

so in AP,

a+b =2b

(k+9 )+ (2k+7)= 2(2k-1)

k+9+2k +7= 4k-2

3k + 16 = 4k -2

3k-4k = -2-16

-k = -18

k= 18

for k = 18 in the terms k+9, 2k-1, in AP ......:....

Answer 2

Explanation:

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