For what value of k will k+9, 2k-1 and 2k+7 are the concecutive terms of an ap?
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First term of the ap = k+9
Common Difference = 2k-1-(k+9)
= 2k-1-k-9
= k-10
OR
2K+7 -(2K-1)=K-1
2K+7-2K+1=K-1
K-1=8
K=9 (ANSWER)
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