For what value of k will k+9,2k -1 and 2k+7 become consecutive terms of an AP
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as D = a2 -a1
so,2k-1-(k+9)=2k+7-(2k-1)
2k-1-k-9=2k+7-2k+1
k-10=8
k=8+10
k=18
so,2k-1-(k+9)=2k+7-(2k-1)
2k-1-k-9=2k+7-2k+1
k-10=8
k=8+10
k=18
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