For what value of k will k + 9, 2k - 1 and
Ok + 7 are the consecutive terms of an AP
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Answer:
k=7
Step-by-step explanation:
we know that a+c/=b
for three terms of an AP
therefore k+9 +k+7 / 2= 2k-1
2k+16= 4k-2
k= 7
aadi740:
your right answer
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