Question

For what value of K will K+9,2k-1and 2k+7are consecutive Terms of A .p.

Answer 1

Answer:

Step-by-step explanation:put the formula tn=a(n-1)d in which a=k+9

Answer 2

Answer:

THE TERMS ARE :  (K + 9) , ( 2K - 1 ) , ( 2K + 1 )

∴ a1 = k + 9 , a2 = 2k - 1 , a3 = 2k + 7

NOW , a2 - a1 = a3 - a2

⇒2k - 1  - k - 9 = 2k + 7 - 2k + 1

⇒k - 10 = 8

⇒k = 18

Hence , value of k = 18