for what value of k will k+9,2k-1and 2k+7are the consecutive terms of an AP
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It's not my answer which you have marked as brainliest .
It's the other one
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i am sorry to hear that, You have mistakenly chosen, So If you want the Brainliest , Please do contact Moderators, It's ok even If I don't have it !
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In general, if 3 consecutive terms are in A.P, Then the mean of first and last terms equal to middle term,
That is, If a,b,c are 3 consecutive terms of A.P, Then, (a+c)/2 = b,
To find the value of k, Just apply the above formula,
=> (k+9+2k+7)/2 = 2k-1,
=> 3k+16 = 4k-2 (Multiplied both the equations by 2),
=> 18 = 4k-3k,
=> 18 = k,
Therefore if k+9, 2k-1, 2k+7 need to be 3 consecutive terms of A.p, Then the value of k should be 18,
Hope you understand, Have a great day! ,
Thanking you, Bunti 360!
That is, If a,b,c are 3 consecutive terms of A.P, Then, (a+c)/2 = b,
To find the value of k, Just apply the above formula,
=> (k+9+2k+7)/2 = 2k-1,
=> 3k+16 = 4k-2 (Multiplied both the equations by 2),
=> 18 = 4k-3k,
=> 18 = k,
Therefore if k+9, 2k-1, 2k+7 need to be 3 consecutive terms of A.p, Then the value of k should be 18,
Hope you understand, Have a great day! ,
Thanking you, Bunti 360!
Thank you for choosing my answer as the Brainliest answer !,
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