For what value of k will k+9,2k-1and2k+7 are th e consecutive terms of an ap?
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Answered by
4
use method 2b=a+c
Here a=first value b=2nd value And c= third value
Here a=first value b=2nd value And c= third value
Answered by
5
as k+9,2k-1,2k+7 are in ap
2(2k-1)=k+9+2k+7
4k-2=3k+16
k=18
2(2k-1)=k+9+2k+7
4k-2=3k+16
k=18
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