Question

for what value of k will k+9,2k-1anf2k+7be the consecutive termsof an a.p

Answer 1

HEYA
YOUR ANSWER

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a1 = k+9
a2 = 2k-1
a3 = 2k+7

d = a2 - a1
d= 2k-1-k-9
d = k-10

d = a3-a2
k-10 = 2k+7-2k+1
k=18

THREE CONSECUTIVE TERMS ARE

a1=k+9=18+9=27
a2=2k-1=36-1=35
a3=2k+7=36+7=43

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HOPE IT HELP YOU

Answer 2

Hope u like my process
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IF X, Y, Z are in AP, then It can be written that

=> Y- X = Z - Y

=> 2Y = Z+ X

Now,
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$= > \blue{2 (2k - 1)} = \blue{(k + 9) + (2k + 7)} \\ \\ = > \blue{4k - 2} = \blue{3k + 16} \\ \\ = > \blue{4k - 3k} = \blue{ 16 + 2} \\ \\ = > \boxed{k = \underline{ \bf \green{18}}}$
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Hence the value of k is 18.

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