For what value of k will make the three points(1,4),(-3,16)and (k,-2)collinear?
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Answer:
k=3
Step-by-step explanation:
Consider
a(1,4), b(-3,16) and c(k,-2).
Form a matrix for solution'
°in the attached picture°
Expand from R¹
=1(16+2) -4(-3-k) +1(6-16k)
=18+12+4k +6-16k
=36+12k
The points a, b and c are collinear (given).
=) 0=36+12k
-36/12=k
k=3
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