Question

For what value of 'k' will the consecutive numbers 2k+1,2k+3and 5k-1are in A.P.
​

Answer 1

Answer:

k=2

Step-by-step explanation:

for 3 terms a, b and c to be in AP

the must condition is 2b=a+c

so 2(2k+3)= (2k+1) +( 5k-1)

so 4k+6= 7k

=> 3K=6

so k=2

hope it helps