Question

For what value of k will the consecutive terms 2k+1 ,3k+3 and 5k-1 form an AP

Answer 1

The value of k is 2 for it to be an AP

Answer 2

If the terms are in A.P the common difference between consecutive terms should be equal
Common difference = a2-a1=a3-A2
3k+3-2k-1=5k-1-3k-3
K+2=2k-4
K-6=0
k=6