Question

For what value of k will the consecutive terms 2k + 1, 3k + 3, and 5k - 1 form an AP?


If anybody knows then pls answr it....!!!!​

Answer 1

Answer:

Terms of AP

2k+1, 3k+3, 5k-1

Now,

3k+3 - (2k+1) = 5k-1 - (3k+3)

2(3k+3) = 5k-1 +2k+1

6k + 6 = 7k

K = 6 ✔️

Answer 2

Answer: 6

Step-by-step explanation: