Question

For what value of k will the consecutive terms 2k +1,3k+3 and 5k_1 form an a.p

Answer 1

Answer:

let A=2k+1

B=3k+3

C=5k-1

In an A.P,difference b/w every term is same.

=> B-A=C-B

=> 3k+3-(2k+1) = 5k-1-(3k+3)

=> 3k+3-2k-1 = 5k-2-3k-3

=> k+2 = 2k-5

=> k=7

hope it helps you.....✌✌