For what value of k will the consecutive terms 2k+1,3k+3 and 5k_1 from an
a.p.
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Hey there!!
Let 2k+1, 3k+3, and 5k-1 are the three terms of this AP
we know diffrence among the terms is always equal by this context ,
a2 -a1 = a3 - a2
=> (3k+3)-( 2k+1) = (5k-1) -( 3k+3)
=> 3k +3 -2k -1 = 5k-1 -3k-3
=> k +2 = 2k -4
=> k-2k = -4-2
=> -k = -6
=> k. = 6
u can verify it too by k =6 in all the the given terms
hope this helps u !!
Let 2k+1, 3k+3, and 5k-1 are the three terms of this AP
we know diffrence among the terms is always equal by this context ,
a2 -a1 = a3 - a2
=> (3k+3)-( 2k+1) = (5k-1) -( 3k+3)
=> 3k +3 -2k -1 = 5k-1 -3k-3
=> k +2 = 2k -4
=> k-2k = -4-2
=> -k = -6
=> k. = 6
u can verify it too by k =6 in all the the given terms
hope this helps u !!
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