Question

.For what value of k will the consecutive terms 2k + 1, 3k + 3, and 5k -1 form an Arithmetic progression.?

Answer 1

Answer:

As it is in A.P to therefore difference between the two consecutive terms will be same

So, (2k+1) - (3k+3) = (3k+3) - (5k-1)

2k+1-3k-3 = 3k+3-5k+1

-k-2 = -2k+4

-k+2k-2 = 4

-k + 2k = 4+2

k = 6