Question

for what value of k will the consecutive terms 2k+1,3k+3 and 5k-1 form an ap

Answer 1

Answer:

Here’s Your Ans

Step-by-step explanation:

Let

a1 = 2k+1

a2= 3k+3

a3 = 5k-1

given a1,a2,a3 are in ap

therefore

a2- a1 = a3-a2

3k+3-(2k+1) = 5k-1- (3k+3)

3k+3-2k-1 =5k-1-3k-3

k+2 =2k-4

k-2k =-4-2

-k = -6

k= 6