Question

for what value of k will the consecutive terms 2k+1,3k+3and5k_1 form an A.P.?

Answer 1

Hey !!!

As we know that the consecutive term of an Ap is equal to each common difference .

means , t2 - t1 = t3 - t2 = d ( common difference)

so, here
t1 = 2k +1 .
t2 = 3k + 3
t3 = 5k -1

so, 3k + 3 - (2k +1 ) = 5k -1 -(3k+3)

=] 3k + 3 - 2k -1 = 5k -1 - 3k -3

=> k +2 = 2k -4

=> 4 +2 = k

hence k = 6 Answer

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@Rajukumar111