for what value of k will the consecutive terms 2k+1,3k+3and 5k-1form an Ap
Answers
Answered by
13
The formula of AP series is ----------
b-a = c-b
a+c=2b
Let,
a=2k+1
b=3k+3
c=5k-1
Now,
(3k+3)-(2k+1) = (5k-1)-(3k+3)
(2k+1)+(5k-1) = 2(3k+3)
7k = 6k+6
k = 6 [Ans.]
Hope it will help you .
b-a = c-b
a+c=2b
Let,
a=2k+1
b=3k+3
c=5k-1
Now,
(3k+3)-(2k+1) = (5k-1)-(3k+3)
(2k+1)+(5k-1) = 2(3k+3)
7k = 6k+6
k = 6 [Ans.]
Hope it will help you .
Explode:
Yes
Answered by
1
This is your answer.
hope it helps you
sorry actually in answer there's a little bit correction in equation I wrote (3x-3) but it was(3x+3) so anser after doing will come 6
hope it helps you
sorry actually in answer there's a little bit correction in equation I wrote (3x-3) but it was(3x+3) so anser after doing will come 6
Attachments:
Similar questions
Biology,
8 months ago
Math,
8 months ago
English,
8 months ago
Math,
1 year ago
Accountancy,
1 year ago
Business Studies,
1 year ago