Question

For what value of “k” will the equation (2kx2 + x +2)=0 have equal roots?

Answer 1

Given Eqn. is 2kx^2 + x + 2

since, eqn has real roots

so, b^2 - 4ac = 0

=> 1 - 4(2k)(2) = 0

so, k = 1/16

Answer 2

Answer:

Step-by-step explanation:

eqn have equal roots -

D=0

0= b2-4ac

0=1-4 (2k)(2)

0=1-16k

16k=1

k=1/16

Hope it will help u