Question

For what value of k will the equation x+2y+(11-k)=0 and 2x+ky+(10+k)=0 represent the coincident line

Answer 1

Answer:

for it to be consistent ---

a1/a2 =b1/b2 =c1/c2

Step-by-step explanation:

given that

x+2y-(11-k) =0---------1

2x+ky+(10+k)=0--------2

a1/a2 = 1/2

b1/ b2= 2/k

c1/c2 = 11-k/10+k

1/2=2/k

k=2*2

k=4

thank you

Answer 2

For k = 4, the equation x+2y+(11-k)=0 and 2x+ky+(10+k)=0 will represent the coincident line.

Given,

x+2y+(11-k)=0 and 2x+ky+(10+k)=0

To find,

For what value of k will the equations represent the coincident line?

Solution,

It is given that

x+2y-(11-k) =0---------1

2x+ky+(10+k)=0--------2

a1/a2 = 1/2

b1/ b2= 2/k

c1/c2 = 11-k/10+k

Since lines are coincident,

1/2 = 2/k

k = 2 x 2

k = 4

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