Question

For what value of k will the equation x+2y+7= 0, 2x+ky+14=0 represent coincident lines.

Answer 1

Hope u understand.......

Answer 2

Answer:

k = 4

Step-by-step explanation:

As per the given question,

We can say accordingly that,

For when two lines are termed as the coincident lines we can say that the ratio of the co-efficient of the lines are equal.

i.e.

ax + by + c = 0 and px + qy + z = 0

then,

$\frac{a}{p}=\frac{b}{q}=\frac{c}{z}$

Therefore, for the lines,

x + 2y + 7 = 0

and,

2x + ky + 14 = 0

We can say on applying the condition, we get,

$\frac{1}{2}=\frac{2}{k}=\frac{7}{14}\\k=4$

Therefore, the required value of 'k' is 4.