Question

For what value of k will the following pair of equations have no solution? K X + 3 Y =K - 3 and 12 + K Y = K.
PLEASE GIVE THE ANSWER STEP BY STEP.
AND PLEASE DON'T POST THE SILLY ANSWER.

Answer 1

for no solution,
a1/a2 =b1/b2 not equal to c1/c2
so a1 = k, a2 = 12 ,b1 = 3 ,b2 = k
k/12 = 3/k
cross multiplying,
k^2 =36
k = 6 hope you helped