Question

for what value of k will the following pair of linear equation have infinity many solution kx+5y-(k -3)=0 ,12x+10y-12=0​

Answer 1

Step-by-step explanation:

infinity many solution = a1/a2=b1/b2=c1/c2

a1=k, a2=12 b1=5, b2=10 c1=-(k-3), c2=-12

a1/a2=b1/b2

k/12=5/10

cross multiply we get

10k=60

k=60/10

k=6