Question

For what value of k will the following pair of linear equation have infinitely many number of solutions 3x+y=1 and (2k-1)x+(k-1)y =2k+1

Answer 1

Answer:

if it has infinite solutions then : a1/a2 =b1/b2=C1/c2.

so , 3/2k-1= 1/k-1=1/2k+1.

let us take 3/2k+1 =1/k-1.1/

then , 3k-3=2k+1.

3k-2k =1+3.

k=4

let us take, 1/k-1=1/2k+1.

2k+1=k-1.

2k -k =-1-1.

k=-2.

let us take, 3/2k+1 =1/2k+1.

6k+3=2k+1.

6k-2k=1-3.

4k=-2.

k=-1/2.

hence, possible value of k is -1/2 , 4, -2.

Answer 2

Answer: The answer is attached below:

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