Question

for what value of k will the following pair of linear equations have infinitely many solutions kx+ 3y-(k- 3 )is equal to zero 12 x + k y - k is equal to zero

Answer 1

putting x=1 & y=0
we get, 1k + 3x0-k-3
2k-3=0
2k=3
k=3/2
12x1+kx0-k
12+1k=0
1k=-12
k=-12/1 or -12