Question

for what value of k will the following pair of linear equations have no solution 8x+5y=9; kx+10y=12​

Answer 1

Answer: 2

Step-by-step explanation:

3x + y =1

(2k-1)x+(k-1)y=2k+1

=> 3x+y-1=0

(2k-1)x+(k-1)y-2k-1 =0

We know,

a1/a2 = b1/b2 not equal to c1/c2 has no solution

Now,we have,

a1=3 , b1=1

a2=2k-1 , b2 = k-1

3/2k-1 = 1/k-1

3(k-1) = 2k -1

3k-3 = 2k -1

3k -2k = -1 +3

k = 2

I hope it will help you