Question

For what value of k will the following

system of equations have a unique

solution.

(i) 2x + ky = 1 and 3x – 5y = 7

(ii) x – 2y = 3 and 3x + ky = 1

(iii) 2x + 5y = 7 and 3x – ky = 5​

Answer 1

Answer:

(ii) is the answer .....

Answer 2

We know that,

          For two equations to have unique solutions they must be in the form of

          a1/a2≠b1/b2

Now,

      [i] a1=2 and a2=3

          b1=k and b2=-5

    2/3≠-k/5

   -k≠10/3

    k≠-10/3

Therefore the value of k can be anything other than -10/3

[ii] a1=1 and a2=3

    b1=-2 and b2=k

   1/3≠-2/k

    k≠-6

therefore the value of K can be anything other than -6

[iii] a1=2 and a2=3

    b1=5 and b2=-k

    2/3≠-3/k

    k≠-9/2

Therefore the value of K can be anything other than -9/2

HERE IS THE ANSWER FOR THE QUESTION YOU ASKED.