Question

for what value of k will the following system of linear equation have no solution 3 X + Y = 1 ;(2 k - 1) X + (K - 1) y = 2 k + 1​

Answer 1

Step-by-step explanation:

3x+y=1 -(1)

(2k-1)x+(k-1)y=(2k+1) -(2)

a1=3,a2=2k-1,b1=1,b2=k-1,c1=1,c2=2k+1

FOR no solution,

a1/a2=b1/b2$c1/c2. [let $ is not equal to]

3/(2k-1)=1/(k-1)$1/(2k+1)

from a and b,

3(k-1)=1(2k-1)

3k-2k=3-1

k=2.

from b and c,

1(2k+1)$1(k-1)

2k-k$-1-1

k$-2.

So,k=2 and k$-2.

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