For what value of ‘k’ will the following system of linear equations have no solution? 3x + y = 1, (2k – 1)x + (k – 1)y = 2k + 1
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Answer:
if x =1
3x + y = 1
3(1)+y=1
y=1-3
y=-2 Ans
(2k – 1)x + (k – 1)y = 2k + 1
(2k-1)(1)+ (k-1)(-2)=2k+1
2k-1 -2k+1-1=2k
-1=2k
k=-1/2 Ans
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