For what value of 'k' will the following system of linear equations have infinite number of solutions.
10x+5y-(k-5)=0 and 20x+10y-k=0
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Step-by-step explanation:
a1/a2=b1/b2=c1/c2
10/20=5/10=k-5/k
1/2=k-5/k
k=2k-10
-k=-10
k=10
this is the answer
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