Question

For what value of k will the following system of linear equations have no

solution ?

3x + y = 1

(2k – 1)x + (k – 1)y = 2k + 1​

Answer 1

The rule is that.... a1÷a2=b1÷b2 not = c1÷ c2

It will become - 3x+y-1=0

(2k-1)x + (k-1)y - (2k+1)=0

and the answer would be k = 2....

Answer 2

Answer and Step-by-step explanation:

For what value of k the following system of linear equations has no solution?

• 3x + y = 1
• (2k−1)x + (k−1)y = 2k + 1