For what value of k will the following system of linear equations have no
solution ?
3x + y = 1
(2k – 1)x + (k – 1)y = 2k + 1
Answers
Answered by
2
The rule is that.... a1÷a2=b1÷b2 not = c1÷ c2
It will become - 3x+y-1=0
(2k-1)x + (k-1)y - (2k+1)=0
and the answer would be k = 2....
Answered by
1
Answer and Step-by-step explanation:
For what value of k the following system of linear equations has no solution?
- 3x + y = 1
- (2k−1)x + (k−1)y = 2k + 1
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