Question

For what value of k will the pair of equation kx+3y=k-3 and 12×+ky=k has many solutions

Answer 1

Step-by-step explanation:

kx+3y=k-3

kx+3y-(k-3)=0. _ __(1)

and

12x+ky=k

12x+ky-k=0

these equations are of the form of A1x+B1y+C1=0 and A2x +B2y+C2=0

where,

A1=k,B1=3and C1= -k+3

and

A2=12,B2=k andC2= -k

A1/A2,B1/B2 and C1/C2

k/12=3/k

k^2= 12×3

k=√36=6