For what value of k will the pair of equations x + 2y + 7 = 0 and 2x – ky + 14 = 0 represent
coincident lines
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Answered by
0
Answer:
Here is ur answer...!!!
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→ x+2y+7=0
2x+ky+14=0
⇒ a₁ = 1 , b₁ = 2 , c₁ = 7
a₂ = 2 , b₂= k , c₂ = 14
COINCIDENT LINES OR SOLUTION : a₁/a₂ = b₁/b₂ = c₁/c₂
1/2 = 2/k = 7/14
∴ 1/2 = 2/k
so, k = 4
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Answered by
0
Answer:
k = -4
Step-by-step explanation:
Given x + 2y + 7 = 0 and 2x – ky + 14 = 0
For when two lines are termed as the coincident lines we can say that the ratio of the co-efficient of the lines are equal.
i.e. ax + by + c = 0 and px + qy + z = 0
then,
a/p = b/q = c/z
So,
from the given equations we may write:
1/2 = 2/(-k) =7/14
=> 1/2 = 2/(-k)
=> k = (-2) × (2)
=> k = -4
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