Question

for what value of k will the polynomial x square minus x minus 2k plus 2 has one of the zeros as minus 4​

Answer 1

Answer:

k=9

Step-by-step explanation:

x^2-2k+2=0, if one of thr roots is -4

the p(-4) = (-4)^2 -2k +2=0

0=16+2-2k

18=2k

k=9

Answer 2

${\purple{\bf{Hola!!}}}$

Given:-

x²-2k+2

has -4 as a zero

to find:- value of k

p(x)=x²-x-2k+2

p(x)= -4

(-4)²-(-4)-2k+2=0

16+4+2-2k=0

22-2k=0

-2k= -22

k = ${\frac{-22}{-2}}$

k = ${\frac{22}{2}}$

${\blue{\bf{k=-11}}}$