Question

For what value of k will the successive terms 2k+1, 3k+3and 5k-3 from an AP

Answer 1

hope this helps you..

Answer 2

let terms be in ap then
sum of 3 terms of an AP=(1st term+last term)3/2
                                      =(2k+1+5k-3)*3/2
                                      =(7k-2)*3/2
sum of the 3 terms is also=(2k+1)+(3k+3)+(5k-3)
                                         =10k+1
10k+1=(7k-2)*3/2
20k+2=21k-6
21k-20k=6+2
k=8