Math, asked by heena8148, 4 months ago

For what value of K, will the system of equation has a unique solution. x+2y =5
3x+ky-15=0​

Answers

Answered by taqueerizwan2006
2

Answer:

x=5-2y

3(5-2y)+ky-15=0

15-6y+ky-15=0

ky=6y

k=6 ANS.

Answered by sandeepgond8928
5

Answer:

given information unik solution

a1/a2not equal to b1/b2 not equal to c1/c2

comparing equation 1, equation 2 with a1x+b1y+c1=0 a2x+b2y+c2=0

x-ky-2=0 3x+2y+5=0

a1x+b1y+c1=0 a2x+b2y+c2=0

a1=1 b1=-k c1=-2 a=3 be=2 c2=5

1/3not equal to -k/2 a1/a2 not equal to b1/b2

【k not equal to -2/3】

k=R-{2/3}

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