Question

for what value of k will the system of equation has no solution (3x+1)x+3y-2=0 & (k^2+1)x+k-2y-5=0

Answer 1

Answer:

Given system of equations is:

3x+y=1 and

(2k-1)x+(k-1)y=2k+1

They can be rewrite as:

3x + y - 1 = 0 and

(2k-1)x + (k-1)y - (2k+1) = 0

We know that, for the given system to have no solution ,

Step-by-step explanation:

We know that, for the given system to have no solution ,

you can see the figures that is the answer