For what value of K with the term 2k+1,8and 3k form an ap
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By using formula = 2b=a+c
A=2k+1
B=8
C=3k
2(8)=2k+1+3k
16=5k+1
5k=16-1
5k=15
K=15/5
K=5
Hope it helps
A=2k+1
B=8
C=3k
2(8)=2k+1+3k
16=5k+1
5k=16-1
5k=15
K=15/5
K=5
Hope it helps
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